// 给你一个数组 items ，其中 items[i] = [typei, colori, namei] ，描述第 i 件物品的类型、颜色以及名称。
// 另给你一条由两个字符串 ruleKey 和 ruleValue 表示的检索规则。
// 如果第 i 件物品能满足下述条件之一，则认为该物品与给定的检索规则 匹配 ：
//     ruleKey == "type" 且 ruleValue == typei 。
//     ruleKey == "color" 且 ruleValue == colori 。
//     ruleKey == "name" 且 ruleValue == namei 。
// 统计并返回 匹配检索规则的物品数量 。

// 示例 1：
// 输入：items = [["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], ruleKey = "color", ruleValue = "silver"
// 输出：1
// 解释：只有一件物品匹配检索规则，这件物品是 ["computer","silver","lenovo"] 。

// 示例 2：
// 输入：items = [["phone","blue","pixel"],["computer","silver","phone"],["phone","gold","iphone"]], ruleKey = "type", ruleValue = "phone"
// 输出：2
// 解释：只有两件物品匹配检索规则，这两件物品分别是 ["phone","blue","pixel"] 和 ["phone","gold","iphone"] 。注意，["computer","silver","phone"] 未匹配检索规则。

// 提示：
//     1 <= items.length <= 104
//     1 <= typei.length, colori.length, namei.length, ruleValue.length <= 10
//     ruleKey 等于 "type"、"color" 或 "name"
//     所有字符串仅由小写字母组成

/**
 * @param {string[][]} items
 * @param {string} ruleKey
 * @param {string} ruleValue
 * @return {number}
 */
var countMatches = function(items, ruleKey, ruleValue) {
    let num = 0
    items.map(item => {
        (item[0] == ruleValue && ruleKey == 'type') ||
        (item[1] == ruleValue && ruleKey == 'color') ||
        (item[2] == ruleValue && ruleKey == 'name') ? num++ : num
    })
    return num;
};

console.log(countMatches([["phone","blue","pixel"],["computer","silver","lenovo"],["phone","gold","iphone"]], "color", "silver"));


